The other way around: It shows that I always exists, independent of the number o... | Hacker News

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Lichtso on July 20, 2021 | parent | context | favorite | on: Megaverse: Simulating Embodied Agents at One Milli...

The other way around: It shows that I always exists, independent of the number of observing copies (even if it is 0). Basically: There are only weak pointers and no strong pointer, yet it never gets deallocated or was ever allocated to begin with.

Tenoke on July 20, 2021 [–]

I see. Under something like MUH it wouldn't matter, yes. But then nothing matters under MUH anyway.

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